Taller de ecuaciones lineales
Determinar la solución de las siguientes ecuaciones.
$$1) \frac{4\left(x+2\right)}{5}=7+\frac{5x}{13}$$
$$2) \frac{x+4}{14}+\frac{x+4}{6}=2$$
$$3) \frac{x+20}{9}+\frac{3x}{7}=6$$
$$4) \frac{x-8}{7}+\frac{x-3}{3}+\frac{5}{21}=0$$
$$5) \frac{5(x+5)}{8}-\frac{2(x-3)}{7}=5\frac{19}{28}$$
$$6) \frac{x}{2}+\frac{x}{3}-\frac{x}{4}+\frac{x}{5}=7\frac{5}{6}$$
$$7) \frac{3x}{4}-\frac{6}{17}(x+10)-\left(x-3\right)=\frac{x-7}{51}-4\frac{3}{4}$$
$$8) 3+\frac{x}{4}=\frac{1}{2}\left(4-\frac{x}{3}\right)-\frac{5}{6}+\frac{1}{3}\left(11-\frac{x}{2}\right) $$
$$9) \frac{1}{5}(x-8)+\frac{x+4}{4}+\frac{x-1}{7}=7-\frac{23-x}{5}$$
$$10) x-\left(3x-\frac{2x-5}{10}\right)=\frac{1}{6}(2x-57)-\frac{5}{3}$$
$$11) \frac{2x-5}{5}+\frac{x-3}{2x-15}=\frac{4x-3}{10}-1\frac{1}{10}$$
$$12) \frac{4(x+3)}{9}=\frac{8x+37}{18}-\frac{7x-29}{5x-12}$$
$$13) \frac{\left(2x-1\right)\left(3x-8\right)}{6x\left(x+4\right)}$$
$$14) \frac{2x+5}{5x+3}+\frac{2x+1}{5x+2}=0$$
$$15) \frac{4}{x+3}-\frac{2}{x+1}=\frac{5}{2x+6}+\frac{2\frac{1}{2}}{2x+2}$$
$$16) \frac{7}{x-4}-\frac{60}{5x-30}=\frac{10\frac{1}{2}}{3x-12}-\frac{8}{x-6}$$
$$17) \frac{3}{4-2x}+\frac{30}{8(1-x)}=\frac{3}{2-x}+\frac{5}{2-2x}$$
$$18) \frac{25-\frac{x}{3}}{x+1}+\frac{16x+4\frac{1}{5}}{3x+2}=5+\frac{23}{x+1}$$
$$19) \frac{30+6x}{x+1}+\frac{60+8x}{x+3}=14+\frac{48}{x+1}$$
$$20) \frac{x}{x-2}-\frac{x+1}{x-1}=\frac{x-8}{x-6}-\frac{x-9}{x-7}$$
